1
00:00:00,799 --> 00:00:02,795
The first question asks, if we're given
2
00:00:02,795 --> 00:00:05,121
this power law and we put it on a log-log
3
00:00:05,121 --> 00:00:08,105
plot, what will the slope of the line be?
4
00:00:08,105 --> 00:00:12,693
Remember that if we take the logarithm of
5
00:00:12,693 --> 00:00:17,136
both sides of this y = x ^-3 equation, we
6
00:00:17,136 --> 00:00:24,455
get the log of y is equal to -3 times the
7
00:00:24,455 --> 00:00:28,763
log of x. That is just a rule we learned
8
00:00:28,763 --> 00:00:31,127
in an earlier unit when we talked about
9
00:00:31,127 --> 00:00:35,161
logarithms. Ok, now if we plotted
10
00:00:35,161 --> 00:00:40,002
log(y) vs log(x) that is a straight line
11
00:00:40,002 --> 00:00:45,462
with slope -3, so the answer is B.
12
00:00:45,462 --> 00:00:49,098
Problem 2, we see that this is a straight
13
00:00:49,098 --> 00:00:55,064
line on a log-log plot with slope 1/4,
14
00:00:55,064 --> 00:00:56,535
and so the power law is going to have an
15
00:00:56,535 --> 00:00:59,113
exponent of 1/4, and it's going to be
16
00:00:59,113 --> 00:01:04,159
y = x ^ 1/4