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Our first question was how many microstates
give rise to the Win macrostate.
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Well, this one was pretty easy because we can
just enumerate all the possibilities.
3
00:00:10,941 --> 00:00:14,286
We have apple-apple-apple,
orange-orange-orange, and so on.
4
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So the correct answer is 5.
5
00:00:20,598 --> 00:00:23,556
Question 2 was a little more tricky.
6
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That question asks how many microstates
give rise to the Lose macrostate,
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that is, not all three windows
showing the same fruit.
8
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Well, the easiest way to answer that is
to first figure out
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how many total possible microstates
there are for this whole system.
10
00:00:43,274 --> 00:00:46,614
And then subtract out the ones
that we know are Win microstates.
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00:00:46,689 --> 00:00:49,443
And then we're left with the
Lose microstates.
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00:00:50,822 --> 00:00:56,682
So our first question is,
"How many possible microstates are there total?"
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To calculate that we notice that
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for the first window there are total of
five possible fruits that it could be,
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and for each one of those there are five
possible fruits that the second window could be,
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and for each one of those there are five
possible fruits that the third window could be.
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00:01:21,470 --> 00:01:28,153
So we get the total number is
5 times 5 times 5, which is 125.
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OK, the answer to this one is 125,
but we're not done yet.
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That was the total number of microstates.
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The number of Lose microstates is the total
number minus the number of Win microstates.
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00:01:42,209 --> 00:01:44,918
So if you remember that the
Win microstates, there are five of them.
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So the total number of
Lose microstates is 120.
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That is 125 minus 5.